# Annotated Solution to the Jotto Puzzle of the Day

## May 8, 2003

curbs - 1
swang - 1
cowps - 2
skimp - 1
ottos - 1
heles - 1
roped - 0

Yay, a zero. And with common letters, too. This promises to be quick.
Let's start by reducing from the zero:

cubs - 1
swang - 1
cws - 2
skim - 1
hls - 1

Since (ts=1), that's only two options, so let's start by assuming the
**s**. Reducing with that gives us:
s(cub=0)(wang=0)(cw=1)(kim=0)(t=0)(hl=0)

We know it must be either the **c** or the **w** (cw=1). However,
the **c** is out (cub=0), and so is the **w** (wang=0). We have a
contradiction, so the **s** is out.

That means there is a **t** (ts=1). With the **s** out, we also know
**cw** (cws=2). Reducing gives us:

tcw(kim=1)(hl=1)

Since there's probably a vowel, let's go with the **i**. That gives us
2 combinations, **tcwih** and **tcwil**. Anagramming turns up the
solution: **witch**.

kevin@aq.org

Jotto Puzzle of the Day

Jotto

Return to Kevin's aq.org page.

Last modified: 08 May 2003